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Topic: Science
Number of pages / Number of words: 7 / 1888
Essay's paper body

Hence, the mass of ascorbic acid reacted can be calculated.

Results

Mass of NaIO3 : 0.63 g

? Molarity of 250cm3 standard NaIO3 solution : (0.63 ?197.89 ? 0.25)M = 0.012734 M

By equation III, no. of moles of I2 formed = no. of moles of NaIO3 x 3 ?10

= (0.63 ?197.89 x 0.3)mol

= 9.550761x10-4 mol

By equation II, no...


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of moles of I2 formed = no. of moles of NaIO3 x 3 ?10

= (0.63 ?197.89 x 0.3)mol

= 9.550761x10-4 mol

By equation II, no. of moles of S2O32- needed to react all I2 = no. of moles of I2 formed x 2

= (9.550761x10-4 x 2)mol

= 1.910152x10-3 mol

The table below shows the standardization of Na2S2O3 solution by titration:-

Trial 1st 2nd

Final reading /cm3 32...


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General points of the essay

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