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| Number of pages / Number of words: |
2 / 505 |
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Marks less than 5 are 0, 1, 2, 3, and 4.
Hence we should calculate the probability that its mark in the exam is less or equal to 4 : P(X?4)=P(0)+P(1)+P(2)+P(3)+P(4)
UOPN CALCULATING THE MISSING PROBABILITIES WE HAVE
P(X?4)=0.1074+0.2684+0.3020+0.2013+0.0881)=0.9672
The probability that a random variable is less or equal to a value is denoted by P(X?x),and called the cumuative probability
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This is a probability tree for 3 trials.
To calculate the probability that there are x successes in n trials,
For each success in the sequence we must multiply by p.
And if there are c successes, there must be (n-x) failures. For each failure we multiply by (1-P).
Thus, the probability for each sequence of branches that produce x successes and n-x failures, is p^x ?(1-p)?^(n-x)
There are a number of branches that yield x successes and (n-x) failures...
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